I have to connect two remote networks, but my client wants to have single DHCP for both networks and all computers in the same C class, let’s say 192.168.27.0/24. This is something similar as described here (EoIP), but I can’t make this working. I will try to explain my configuration.
[LAN1 192.168.27.0/24][ETH 192.168.27.105 - ROUTER1 - WLAN 10.10.11.15][AP][WLAN][AP][WLAN 10.10.5.15 - ROUTER2 - ETH 192.168.27.104][LAN2 192.168.27.0/24]
I did everything as described in 2.9 documentation for EoIP tunnel. I have EoIP between 10.10.11.15 and 10.10.5.15 and it works OK. I bridged tunnel and ethernet card on both routers and give them above addresses, 192.168.27.105 and 192.168.27.104 respectively.
From router 1 I can ping all machines in LAN1 (local network) and bridge interface on router 2, 192.168.27.104, but I can’t ping machines in LAN2. From router 2 same situation, I can ping LAN2 (it’s local network) and bridge interface on router 1, 192.168.27.105, but not machines in LAN1. I disabled ARP for ethernet card and tunnel on both routers and enabled ARP for bridge interface on both. I tried proxy-arp as well, but it didn’t help. What I am doing wrong?
As temporary solution, I had to put another C class on LAN2, let’s say 192.168.28.0/24 and I removed bridges (bridge interfaces) and did routing instead. This works find, I can ping machines all arroung, but netbios doesn’t work this way. So I did some NAT on both routers and netbios work, but machines on LAN1 still don’t see machines from LAN2 (and opposite) in their network neighbourhood, although they can see shares on remote side id they type in IP addresses, let’s say on machine 192.168.27.200 you type in \192.168.28.200 and they you can see shares. I don’t like this way, it’s not elegant.
I checked many similar posts on this forum, but there is no real solution. I don’t need to use EoIP explicitely, I just want, as I said in the topis of this message, to connect two remote networks in the same C class without matter what tunnel I am using or whatever other solution. Please help.