Two hosts, A and B, are connected to a broadcast LAN. Select all the answers showing pairs of IP address/mask which would allow IP connection to be established between the two hosts.
A. A: 10.1.2.66/25 and B: 10.1.2.109/26
B. A: 10.2.2.1/23 and B: 10.2.0.1/22
C. A: 10.1.2.192/24 and B: 10.1.2.129/26
D. A: 10.2.1.0/23 and B: 10.2.0.1/22
What is the trick to select correct answers quickly?
Address: 10.1.2.66 00001010.00000001.00000010.0 1000010
Netmask: 255.255.255.128 = 25 11111111.11111111.11111111.1 0000000
Wildcard: 0.0.0.127 00000000.00000000.00000000.0 1111111
=>
Network: 10.1.2.0/25 00001010.00000001.00000010.0 0000000
HostMin: 10.1.2.1 00001010.00000001.00000010.0 0000001
HostMax: 10.1.2.126 00001010.00000001.00000010.0 1111110
Broadcast: 10.1.2.127 00001010.00000001.00000010.0 1111111
Hosts/Net: 126 Class A, Private Internet
Address: 10.1.2.109 00001010.00000001.00000010.01 101101
Netmask: 255.255.255.192 = 26 11111111.11111111.11111111.11 000000
Wildcard: 0.0.0.63 00000000.00000000.00000000.00 111111
=>
Network: 10.1.2.64/26 00001010.00000001.00000010.01 000000
HostMin: 10.1.2.65 00001010.00000001.00000010.01 000001
HostMax: 10.1.2.126 00001010.00000001.00000010.01 111110
Broadcast: 10.1.2.127 00001010.00000001.00000010.01 111111
Hosts/Net: 62 Class A, Private Internet
As mentioned, you can use the internet or any software on your PC during a MikroTik exam.
Simply put it into an IP Calculator on the web or on your PC and see if the IP pairs can communicate directly.
Thank you very much, Pateutz.
So, still no shortcut, really has to calculate one by one and compare. Time consuming.