Hello friends, I have a pool of IP / 29 and I want to give a client a unique IP address, but I do not want to use PPPoE, I want to do it by direct Ethernet, could you help me with the configuration please.
Currently this is my configuration in my central Routerboard
[BELITS@RB4011iGS+RM_R&M] > ip address print
Flags: X - disabled, I - invalid, D - dynamic
ADDRESS NETWORK INTERFACE
1 ;;; WAN UFINET
138.186.23.166/30 138.186.23.164 ETH1
3 ;;; IP PUBLICA CLIENTE
181.78.15.250/29 181.78.15.248 ETH10
[BELITS17@RB4011iGS+RM_R&M] > ip route print
Flags: X - disabled, A - active, D - dynamic,
C - connect, S - static, r - rip, b - bgp, o - ospf, m - mme,
B - blackhole, U - unreachable, P - prohibit
DST-ADDRESS PREF-SRC GATEWAY DISTANCE
0 A S 0.0.0.0/0 138.186.23.165 1
1 ADC 138.186.23.164/30 138.186.23.166 ETH1 0
2 ADC 181.78.15.248/29 181.78.15.250 ETH10 0
In my client this is the configuration:
[ANDALUCIA@MikroTik] > ip address print
Flags: X - disabled, I - invalid, D - dynamic
ADDRESS NETWORK INTERFACE
0 10.10.10.1/24 10.10.10.0 ether2
1 181.78.15.251/29 181.78.15.248 ether1
[ANDALUCIA@MikroTik] > ip route print
Flags: X - disabled, A - active, D - dynamic,
C - connect, S - static, r - rip, b - bgp, o - ospf, m - mme,
B - blackhole, U - unreachable, P - prohibit
DST-ADDRESS PREF-SRC GATEWAY DISTANCE
0 A S 0.0.0.0/0 181.78.15.250 1
1 ADC 10.10.10.0/24 10.10.10.1 ether2 0
2 ADC 181.78.15.248/29 181.78.15.251 ether1 0
My client currently has internet with output at IP address 181.78.15.251/29, but I want to deliver a single IP address other than / 29, how do I do it?