How to set DHCP Server IP Pool?

RouterOS General
1

as subject, i want to know how to set DHCP Server IP Pool to
192.168.3.x/29

so there will be subnets with each subnet is 6 hosts.

example,
there will be user that get ip on these range:
192.168.3.9 - 192.168.3.14
192.168.3.17 - 192.168.3.22
192.168.3.25 - 192.168.3.38
and so on.
the subnet mask for above is 255.255.255.248

how to set it? i don’t any setting about the subnetmask, i just can set
the ip pool without the subnetmask :frowning: and then the user get ip,
example: 192.168.3.9 255.0.0.0 ???

please i need advice

2

Ok i already set this:
ip pool> print

NAME RANGES

0 pool2 192.168.3.1-192.168.3.20
1 pool1 192.168.5.10-192.168.5.20
2 pool3 192.168.3.8/29
3 pool4 192.168.3.16/29

in this case will use the pool3 and pool4 as next pool of pool3

I believe the range of pool3 (192.168.3.8/29) is
192.168.3.9-192.168.3.14 and the range of pool4 (192.168.3.16/29) is
192.168.3.17-192.168.3.22

Then i set:
/ip dhcp-server print
Flags: X - disabled, I - invalid

NAME INTERFACE RELAY ADDRESS-POOL LEASE-TIME ADD-ARP

0 server1 ether1 pool3 3d


i mark the option: Bootp Support and Always Broadcast

Then i set:
ip dhcp-server network> print

ADDRESS GATEWAY DNS-SERVER WINS-SERVER DOMAIN

0 192.168.2.0/24 192.168.2.1 202.158.3.7
202.158.3.6
i set the netmask to 29


but the client get 192.168.3.15 255.0.0.0 :frowning:

then i do test.. change the dhcp-server network to this:
/ip dhcp-server network print

ADDRESS GATEWAY DNS-SERVER WINS-SERVER DOMAIN

0 192.168.3.8/29 192.168.2.1 202.158.3.7
202.158.3.6
but the client get 192.168.3.15 255.255.248, the subnet mask is
correct but the ip address looks like impossible for me, depends on
the pool3 the range is 192.168.3.9-192.168.3.14, so 192.168.3.15 is
should be broadcast address for subnet 192.168.3.8/29

ok, i'm little confuse with the ip dhcp-server network about the address
and netmask.. and it's connectivity with ip pool.

can you help me?

no help?? :unamused: :unamused: