i have fiber optic internet have 2 ip
for explain
10.10.5.1
10.10.5.2
is it possible use 2 ip? 1 mikrotik
ether1 = firber internet
ether2 = blank
ether3 = i want use 10.10.5.2 ( real ip )
ether4 = i want use 10.10.5.1 ( real ip )
Your two IPs from you ISP would be on the ethernet port that your fiber is connected to - in this case, ether 1. What you do with those two IPs is based on your firewall rules. That is similar to what I’m doing with my DSL. Router #1 and router #2 both use three IPs from my ISP (total of six IPs). I have multiple local LANs that each route through a different public IP on the WAN port.
In my case, I replaced multiple consumer grade routers that each had a public static IP from my ISP via a DSL, with a single MicroTik RB750r2 router. I wanted each local LAN to be completely isolated from the other local LANs (having multiple routers made that easy). Here are a few code segments. The first just names the five ethernet ports on the RB750, but was included so it was more obvious what is what later on.
/interface ethernet
set [ find default-name=ether1 ] name=E1-p11_Internet
set [ find default-name=ether2 ] name=E2-p13_201_alt
set [ find default-name=ether3 ] name=E3-p15_202
set [ find default-name=ether4 ] name=E4-p17_203
set [ find default-name=ether5 ] name=E5-p19_211
This next segment defines the multiple IP addresses that appear on the internet port.
/ip address
add address=aaa.bbb.ccc.3/24 comment="Public IP for .202 LAN." interface=\
E1-p11_Internet network=aaa.bbb.ccc.0
add address=aaa.bbb.ccc.9/24 comment="Public IP for .203 LAN." interface=\
E1-p11_Internet network=aaa.bbb.ccc.0
And this segment is the NAT rules that specifies which local LANs route out via which public IP address (to simulate the old individual routers)
Of course there are a bunch of other firewall rules and a bunch of NAT rules, but those are not shown here. Also, of course the aaa.bbb.ccc. is really the first three octets of my public IP addresses.