need to save simple queue output to a file

[IntLDaniel]

@David1234

Try this:

{
    :local filename "usage.txt"
    :local message "Queues:"
    :local queueList [/queue simple find]
    :foreach q in=$queueList do={
        :local qName [/queue simple get $q name]
        :local qTarget [/queue simple get $q target]
        :local qBytes [/queue simple get $q bytes]
        :set message ($message . "\r\n" . "name=\"" . $qName . "\" target=" . $qTarget . " bytes=" . $qBytes)
    }
    /file print file=$filename
    :delay 1
    /file set [/file find name=$filename] contents=$message
}

It is a little hacky maybe, but you can also format the file however you want here too.

If this is the file you are trying to transfer in your other thread, it could all be replaced by one simple API query.

/queue/simple/print
=.proplist=name,target,bytes

That is if you have any programming skills.
The API can be a lot of fun to play with.

I know this is the old thread but I did find this script useful to export queue stats every months (and then reset them). BUT this script was (and still is) limited due to variable size 4096 bytes (see here http://forum.mikrotik.com/t/how-to-write-string-to-a-file-using-script/99624/1 ). That is why if you try to export more than ~20 queues it does not work - the $message variable cannot hold so much strings . So I was thinking if I could write every queue stats separately one by one and append it to the file (the same like /log print append file= … does), but it is probably still not available (ROS 6.49.2 or ROS 7.2RC3) ? Otherwise you have to always read current content of the file first and it is the same problem

Maybe read every queue to separate message variables (message1, message2…) and then somehow write to file all these messages (i.e. 500) one by one to that output file? Is there any solution to this task in 2022? Thanks.