Hi 2 all
Question: How to parse today records in log?
When you make
/log print where message ~"Smth"
You will recieve:
oct/23 16:24:54 info Smth asdasd
oct/24 16:24:54 info Smth asdasd
oct/25 16:24:54 info Smth x124
08:59:21 info Smth ccasdasd
08:59:21 info Smth xar234
08:59:21 info Smth dsfdg
Strings from log for actual date is withoud date, only time
When you make
/log print where message ~"Smth" time~"oct/25"
You will recieve:
oct/25 16:24:54 info Smth x124
When you make
/log print where message ~"Smth" time~"oct/26"
You will recieve: nothing
What is the righ way to parse today log?