parse log "today"

Hi 2 all

Question: How to parse today records in log?

When you make

/log print where message ~"Smth"

You will recieve:

oct/23 16:24:54 info Smth asdasd
oct/24 16:24:54 info Smth asdasd
oct/25 16:24:54 info Smth x124
08:59:21 info Smth ccasdasd
08:59:21 info Smth xar234
08:59:21 info Smth dsfdg

Strings from log for actual date is withoud date, only time


When you make

/log print where message ~"Smth" time~"oct/25"

You will recieve:

oct/25 16:24:54 info Smth x124

When you make

/log print where message ~"Smth" time~"oct/26"

You will recieve: nothing


What is the righ way to parse today log?

i have found a way

/log print where message ~“Smth” time>([/system clock get time] - 24h)
or
/log print where message ~“Smth” time>“00:00:00”


New question: How can i export logs 1 day back (oct25 00:00:00 → oct25 23:59:59)? :sunglasses: