Removing an address from a address-list

RouterOS Scripting
1

I’m trying to make a script which would allow me to remove an address from Address Lists.
As one needs the number of the address entry to be able to remove the address, I thought
of using something like this (lets say 192.168.205.13 is the address I want removed):

:put ([:pick [/ip firewall address-list print terse where address=192.168.205.13] 1 2])

I thought with the above command I would get the addresses entry number and then I would
use:

/ip firewall address-list remove <obtained_number>

But whatever I do I can not get just the number of the entry but I get the whole line instead, ie:

1 D list=Drop_List address=192.168.205.13

Could someone more experienced suggest a solution?

Thank you!

2

/ip firewall address-list {
remove [find address=192.168.205.13]
}

3

So simple when you know what to do! :wink:
Thank you very much!!

4

No problem.