Select rule exact match by fields

RouterOS Scripting
1

Is there any way to select filter rules by fields exact match?
By example, I tried to select only one rule with chain=forward action=accept

 
/ip firewall filter print where action=accept chain=forward 
Flags: X - disabled, I - invalid, D - dynamic 
 0    ;;; Ansible managed: 1
      chain=forward action=accept log=no log-prefix="" 

 1    ;;; Ansible managed: 2
      chain=forward action=accept connection-state=established,related log=no log-prefix=""

As you can see, there is 2 rules match expression, but I want to select only one. When I try to select more common rule, there is more specific rule in output.

2

It not clear what you request is.

Commands gives you what you ask for, så what do you need as an output, from what input?

3

“!” logical NOT :put (!true);
“&&” , “and” logical AND :put (true&&true)
“||” , “or” logical OR :put (true||false);

Standard seems AND

4

Nope, by default ROS searches rules by incomplete match. What I need to do to tell ROS, that I want exact match?
In previous example, I want to get just first resul, not second. Is it posible?

5

Thank you so much! I just didn’t try to use logic operators! And this is just what I need!

/ip firewall filter print where action=accept chain=forward && !connection-state
Flags: X - disabled, I - invalid, D - dynamic 
 0    ;;; Ansible managed: 1
      chain=forward action=accept log=no log-prefix=""