we have a new install coming up where were going to installing a CCR 2216. but the data closet they are providing for us is rather small and so the building is wondering if we can provide with the with specs of how much heat our equipment will produce. ive looked and cannot find this on any spec sheet. i’ve found operating temperature but not how much heat is produced. the only reason im needing this is the building is asking for it and they are wanting this to be an enclosed small room (were talking like 4ft x 4 ft room). Any one know the heat production specs of a CCR 2216?
i think you can use Watts to BTU per hour conversion as a gross way to infer that requirement
ccr2216 product page specifies
Max power consumption 128 W
Max power consumption without attachments 80 W
according to this online converter
https://www.rapidtables.com/convert/power/Watt_to_BTU.html
128 watt/hour can be related as 436.75 BTU/hour
I repeat, this is a gross way to aproach to this, any expert in this matter will criticize this approach
this is a user forum
maybe you can open a ticket to support to obtain an official response
Usually the max power stated by Mikrotik (without attachments) is more than twice the actual average one, if a device like a PC, a router or a switch runs at 100% all the time it means that it is the wrong device (too underpowered).
A 4 feet by 4 feet (and I presume 10 feet of height) is 160 cubic feet.
A (very rough) rule of thumb is around 1 BTU per cubic feet = 10 ° F increase in temperature.
1W=3.41 BTU.
If we use 60 W, we have more like 200 BTU, i.e. 1.25 BTU per cubic feet or 10-15 ° F increase in temperature.
But even with the “full” 128 W or 440 BTU, i.e. 2.75 BTU per cubic feet It becomes 25-30° F.
1 Watt = 1 Joule / second = 3.41 BTU / hour i.e. energy per unit time.
Can we say, 1 BTU per hour per cubic feet = 10 ° F increase in temperature per hour?
Yep, it’s a very approximate the rule of thumb, the 1 to 1.5 is a range that depends on the characteristics of the “envelope”, often 1.33 is used for homes.
If the enclosed small room has a (thick) wooden door you will need much less BTU, if you replace it with a single sheet steel one you will need much more to have 10° F change.
Here we use directly Watts (and meters) and the rule of thumb for dimensioning the heating of a house is (again very roughly) in the range 35-90 W per cubic meter (for a 20-25°C change), so to have 10° C difference you would need 15 - 40 W per cubic meter of installed power, which can be further approximated to 1.5-4 W per degree Celsius.
So, using 2.5 W:
1.21.23=4.32 m3
60W/4.32/2.5=5.5° C → 5.51.8=10° F
with 2W:
60/4.32/2=6.95 C → 6.95*1.8=12.5° F
It sounds more or less correct.