It’ll work, but not optimally since the circuits have different bandwidth. You can make choosing the bigger bandwidth circuit more likely by adding more PCC lines but only assigning the same two marks. As the circuits are roughly 3:1 for bandwidth, you could use
That’s assuming outside2_connection is for the 10 meg circuit. That way, 3 out of 4 times a connection will be put on the 10 meg circuit, and only 1 out of 4 times will it be put on the 3 meg circuit.
Yes, because the route for those routing marks will be unavailable, so packets will drop through to the default routes and saturate whichever interface is still up.
The higher the distance, the less desirable the route is. If both routes are up the route with distance 5 will be chosen as the default route. It would make more sense to have the 10 meg circuit have the shorter distance.
PCC doesn’t allow you to exactly balance bandwidth like that. It’s not a matter of mbps, it’s a matter of connections. Any connection could be taking any bandwidth. It might be a bittorrent connection downloading as fast as the peer will let it, or a telnet connection to a router slowly transmitting keystrokes. But in your original configuration any given connection had a 50/50 chance of ending up on either circuit. By skewing the odds in favor of the 10 meg circuit you’ll make that circuit more likely to be chosen, which makes sense given that it has more bandwidth available. The more connections go through the router, the more traffic will be balanced approaching 3:1.
I tried the code but I couldn’t combine the speed. I draw the internet from one line and it drop continuously. It was better with one line.
I have intel PC as my Mikrotik router with hotspot. I also have Routerboard 450 which I am not using. Is it good idea to use router board to only combine the two line without hotspot setting and use the intel PC for hotspot.
if this is good, what is a good code to make the routerboard combine two unequal lines only (no hotspot)?