Hello, So I have SXT LTE6 kit (SXTR&FG621-EA) reading specs, it states:
Ether2
Passive PoE up to 57V
Max out per port output (input 18-30 V) 600 mA
Max out per port output (input 30-57 V) 400 mA
Max total out (A) 600 mA
Now, This is where it will probably sound as a stupid question, but how much is actually outputted by default? or is it automatically supplied based on the load?
I am trying to power DC12v <5W 1A PoE camera without luck, when connected, mikrotik will light up red led, flashing very slowly… I can’t find which standard of PoE is this and at this point I am wondering if I managed to fry the camera…
Passive PoE so it will depend on the input voltage of SXT.
Where does it say in the specs you can reliably add a 12V-requiring device to it ?
I don’t see it.
So yeah, chances are high you applied already overvoltage to that camera.
It Is automatically supplied based on the supply, i.e. It provides the same voltage with which you power the SXT.
Typically either 24v or 48 v.
The passive PoE has a simple resistance check, if the port is set to auto-on, there is a chance that the full power has not been sent to the camera, if you set It to forced-on the full voltage has surely been sent to the camera.
But there is yet another possibility, there are two PoE connection schemes, mode A and mode B, Mikrotik use mode B, whilst mode A is more common on other brands.
The wires actually used in mode B are those NOT used for data for 100Mb ethernet connection, so, if the camera ethernet port Is 100Mb there is a chance that the pins 4,5,7 and 8 are not connected to anything.
So if you are lucky and the camera Is not fried, you can procure a PoE splitter with 12 V 1A output and power the camera normally from the jack.